思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
NAPA, Calif. -- In the immortal words of song developer Pete Townshend, "Well, who are you? (Who are you? Who, who, who, who?) I really wanna know!" Linux kernel maintainers have the same question: Who are their programmers, and how can the kernel community be sure the code they submit is really theirs? 。关于这个话题，同城约会提供了深入分析
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